Skip to content
Question 103 of 104

Q.Write the values of ff at −4,1,−2,7,0-4, 1, -2, 7, 0 if f(x)={−x+4;−∞<x≤−3x+4;−3<x<−2x2−x;−2≤x<1x−x2;1≤x<70;otherwisef(x)=\begin{cases}-x+4 & ; -\infty<x\le -3\\ x+4 & ; -3<x<-2\\ x^2-x & ; -2\le x<1\\ x-x^2 & ; 1\le x<7\\ 0 & ; \text{otherwise}\end{cases} OR Find the value of kk, if the following equation 12x2+7xy−12y2−x+7y+k=012x^2+7xy-12y^2-x+7y+k=0 represents a pair of straight lines. Further, find whether these lines are parallel or intersecting.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2026Subjective· 5mImportance★★★★★
99% · 103/104 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Evaluating the piecewise function at each given point by matching it to the correct interval gives f(−4)=8f(-4)=8, f(1)=0f(1)=0, f(−2)=6f(-2)=6, f(7)=0f(7)=0, f(0)=0f(0)=0.

The function is defined as:

f(x)={−x+4−∞<x≤−3x+4−3<x<−2x2−x−2≤x<1x−x21≤x<70otherwisef(x)=\begin{cases}-x+4 & -\infty<x\le-3\\ x+4 & -3<x<-2\\ x^2-x & -2\le x<1\\ x-x^2 & 1\le x<7\\ 0 & \text{otherwise}\end{cases}

f(−4)f(-4): since −4≤−3-4\le-3, use f(x)=−x+4f(x)=-x+4: f(−4)=−(−4)+4=4+4=8f(-4)=-(-4)+4=4+4=8.

f(1)f(1): since 1≤1<71\le1<7, use f(x)=x−x2f(x)=x-x^2: f(1)=1−12=1−1=0f(1)=1-1^2=1-1=0.

f(−2)f(-2): since −2≤−2<1-2\le-2<1, use f(x)=x2−xf(x)=x^2-x: f(−2)=(−2)2−(−2)=4+2=6f(-2)=(-2)^2-(-2)=4+2=6.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.