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Question 81 of 104

Q.The function f:[0,2π]→[−1,1]f:[0,2\pi] \to [-1,1] defined by f(x)=sin⁡xf(x) = \sin x is:

(a) one-to-one
(b) onto
(c) bijection
(d) cannot be defined
Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2020MCQ· 1mImportance★★★★★
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f(x)=sin⁡xf(x)=\sin x on [0,2π][0,2\pi] hits every value in [−1,1][-1,1] (onto) but repeats values (not one-to-one).

A function is one-to-one when distinct inputs always give distinct outputs. Here f(0)=sin⁡0=0f(0)=\sin 0=0 and f(π)=sin⁡π=0f(\pi)=\sin\pi=0: two different inputs, 00 and π\pi, map to the same output 00. So ff is NOT one-to-one.

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