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Question 94 of 104

Q.If the function f:[−3,3]→Sf:[-3,3]\to S defined by f(x)=x2f(x)=x^2 is onto, then S is:

(a) [−3,3][-3,3]
(b) [−9,9][-9,9]
(c) [0,9][0,9]
(d) R\mathbf{R}
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Since ff is onto, SS must be the exact range of f(x)=x2f(x)=x^2 on [−3,3][-3,3], which is [0,9][0,9].

For x∈[−3,3]x\in[-3,3], x2x^2 ranges from a minimum of 00 (at x=0x=0) to a maximum of 99 (at x=±3x=\pm3), taking every value in between continuously.

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