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Question 87 of 104

Q.Find the number of subsets of A if A={x:x=4n+1, 2≤n≤5, n∈N}A=\{x : x=4n+1,\ 2 \le n \le 5,\ n \in N\}.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2022Subjective· 3mImportance★★★★★
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A={9,13,17,21}A=\{9,13,17,21\} has 4 elements, so it has 24=162^4=16 subsets.

A={x:x=4n+1, 2≤n≤5, n∈N}A = \{x : x=4n+1,\ 2\le n\le5,\ n\in N\}.

For n=2n=2: x=9x=9. n=3n=3: x=13x=13. n=4n=4: x=17x=17. n=5n=5: x=21x=21.

So A={9,13,17,21}A=\{9,13,17,21\}, which has 4 elements.

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