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Q.

X is a normally distributed variable with mean μ=30\mu = 30 and standard deviation σ=4\sigma = 4. Find P(30<X<35)P(30 < X < 35).

ZZ1.251.2500
Area0.39440.394400
Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2026Subjective· 3mImportance★★★★★
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Standardise: Z=X−μσZ=\frac{X-\mu}{\sigma} gives Z=0Z=0 at X=30X=30 and Z=1.25Z=1.25 at X=35X=35; the area is 0.39440.3944.

Here X∼N(μ=30, σ=4)X\sim N(\mu=30,\ \sigma=4). We convert to the standard normal variate Z=X−μσZ=\dfrac{X-\mu}{\sigma}.

Step 1 — Standardise the limits:

X=30⇒Z=30−304=0,X=35⇒Z=35−304=54=1.25.X=30\Rightarrow Z=\frac{30-30}{4}=0,\qquad X=35\Rightarrow Z=\frac{35-30}{4}=\frac{5}{4}=1.25.

Step 2 — Required probability: …

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