The rate law for a reaction of A, B and L has been found to be rate=k[A]²[B][L]3/2. How would the rate of reac

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\text{rate}=k[A]^2[B][L]^{3/2}

(i) Concentration of [L] is quadrupled

(ii) Concentration of both [A] and [B] are doubled

(iii) Concentration of [A] is halved

(iv) Concentration of [A] is reduced to

\left(\dfrac{1}{3}\right)

and concentration of [L] is quadrupled.

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Step 1 (i). $[L]$ quadrupled, others fixed: new/old rate ratio $=4^{3/2}=(4^{1/2})^3=2^3=8$ . Rate increases 8-fold.

Step 2 (ii). Both $[A]$ and $[B]$ doubled, $[L]$ fixed: ratio $=2^2\times2^1=4\times2=8$ (2 $^2$ from A's order-2 dependence, 2 $^1$ from B's order-1 dependence). Rate increases 8-fold.

Step 3 (iii). $[A]$ halved, others fixed: ratio $=(1/2)^2=1/4$ . Rate falls to 1/4 of the original. …

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Q.The rate law for a reaction of A, B and L has been found to be $\text{rate}=k[A]^2[B][L]^{3/2}$ . How would the rate of reaction change when

Concept understanding — Rate Law and Rate Constant

Q.The rate law for a reaction of A, B and L has been found to be rate=k[A]2[B][L]3/2\text{rate}=k[A]^2[B][L]^{3/2}rate=k[A]2[B][L]3/2. How would the rate of reaction change when

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Q.The rate law for a reaction of A, B and L has been found to be $\text{rate}=k[A]^2[B][L]^{3/2}$ . How would the rate of reaction change when

Unlock everything free for 14 days