For a reaction $x+y+z \rightarrow \text{products}$ the rate law is given by $\text{rate}=k[x]^{3/2}[y]^{1/2}$. What is the overall order of the reaction and what is the order of the reaction with respect to z.

For a reaction x+y+z arrow products the rate law is given by rate=k[x]3/2[y]1/2. What is the overall order of

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x+y+z \rightarrow \text{products}

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Step 1. The given rate law is $\text{Rate}=k[x]^{3/2}[y]^{1/2}$ -- note that z does NOT appear in this expression at all, even though it is one of the three reactants in the balanced equation $x+y+z\rightarrow\text{products}$ .

Step 2. The overall order is the sum of all the exponents that DO appear in the rate law: $\dfrac{3}{2}+\dfrac{1}{2}=2$ . …

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Q.For a reaction $x+y+z \rightarrow \text{products}$ the rate law is given by $\text{rate}=k[x]^{3/2}[y]^{1/2}$ . What is the overall order of the reaction and what is the order of the reaction with respect to z.

Concept understanding — Rate Law and Rate Constant

Q.For a reaction x+y+z→productsx+y+z \rightarrow \text{products}x+y+z→products the rate law is given by rate=k[x]3/2[y]1/2\text{rate}=k[x]^{3/2}[y]^{1/2}rate=k[x]3/2[y]1/2. What is the overall order of the reaction and what is the order of the reaction with respect to z.

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Q.For a reaction $x+y+z \rightarrow \text{products}$ the rate law is given by $\text{rate}=k[x]^{3/2}[y]^{1/2}$ . What is the overall order of the reaction and what is the order of the reaction with respect to z.

Unlock everything free for 14 days