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Write Brief Answer · Q20
Q.

For the reaction 2x+y→L2x+y \rightarrow L find the rate law from the following data.

[x] (M)[y] (M)rate (M s−1\text{M s}^{-1})
0.20.020.15
0.40.020.30
0.40.081.20
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Step 1. Comparing row 1 ([x]=0.2,[y]=0.02[x]=0.2,[y]=0.02, rate =0.15=0.15) and row 2 ([x]=0.4,[y]=0.02[x]=0.4,[y]=0.02, rate =0.30=0.30): [x][x] doubles, [y][y] fixed, rate doubles ⇒\Rightarrow order in x =1=1 (since 21=22^1=2).

Step 2. Comparing row 2 ([x]=0.4,[y]=0.02[x]=0.4,[y]=0.02, rate =0.30=0.30) and row 3 ([x]=0.4,[y]=0.08[x]=0.4,[y]=0.08, rate =1.20=1.20): [x][x] fixed, [y][y] quadruples (0.02→\rightarrow0.08), rate quadruples (0.30→\rightarrow1.20) ⇒\Rightarrow order in y =1=1 (since 41=44^1=4).

Step 3. So rate=k[x]1[y]1=k[x][y]\text{rate}=k[x]^1[y]^1=k[x][y], overall order 2. …

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