Q.Consider the change in oxidation state of bromine corresponding to different emf values as shown in the diagram below: Then the species undergoing disproportionation is
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Step 1. In a Latimer-style diagram, a species in the middle of the chain undergoes disproportionation exactly when the reduction potential to its RIGHT (converting it to the next lower oxidation state) is GREATER than the potential to its LEFT (the potential by which it itself was formed from the higher oxidation state) — because this means the species finds it thermodynamically favourable to be simultaneously oxidised (reversing the left arrow) and reduced (following the right arrow).
Step 2. Check : left potential () = 1.82 V; right potential () = 1.5 V. Since left (1.82) > right (1.5), does NOT disproportionate. …
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.