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Choose the Best Answer · Q8

Q.A current strength of 3.86 A was passed through molten calcium oxide for 41 minutes and 40 seconds. The mass of calcium in grams deposited at the cathode is (atomic mass of Ca is 40 g/mol and 1F = 96500 C).

(a) 4
(b) 2
(c) 8
(d) 6
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Step 1. Convert the time to seconds: 41 min 40 s = 41×60+40=250041\times60+40 = 2500 s.

Step 2. Charge passed: Q=It=3.86×2500=9650Q = It = 3.86\times2500 = 9650 C.

Step 3. The cathode reaction is Ca2++2e−→Ca\text{Ca}^{2+}+2e^- \rightarrow \text{Ca}, so n=2n=2; the electrochemical equivalent is Z=MnF=402×96500Z = \dfrac{M}{nF} = \dfrac{40}{2\times96500} g/C. …

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