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Q.Calculate the standard emf of the cell Cd∣Cd2+ ∥ Cu2+∣Cu\text{Cd} \mid \text{Cd}^{2+} \ \| \ \text{Cu}^{2+} \mid \text{Cu} and determine the cell reaction. The standard reduction potentials of Cu2+/Cu\text{Cu}^{2+}/\text{Cu} and Cd2+/Cd\text{Cd}^{2+}/\text{Cd} are 0.34 V and -0.40 V respectively. Predict the feasibility of the cell reaction.

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Step 1. In the cell Cd∣Cd2+ ∥ Cu2+∣Cu\text{Cd} \mid \text{Cd}^{2+} \ \|\ \text{Cu}^{2+} \mid \text{Cu}, cadmium (left, anode) is oxidised and copper (right, cathode) is reduced, following the standard cell-notation convention.

Step 2. Standard cell emf: Ecello=Ecathodeo−Eanodeo=Eo(Cu2+/Cu)−Eo(Cd2+/Cd)=0.34−(−0.40)=0.74E^{o}_{cell} = E^{o}_{cathode}-E^{o}_{anode} = E^{o}(\text{Cu}^{2+}/\text{Cu}) - E^{o}(\text{Cd}^{2+}/\text{Cd}) = 0.34-(-0.40) = 0.74 V.

Step 3. Cell reaction: anode Cd(s)→Cd2+(aq)+2e−\text{Cd(s)} \rightarrow \text{Cd}^{2+}\text{(aq)}+2e^-; cathode Cu2+(aq)+2e−→Cu(s)\text{Cu}^{2+}\text{(aq)}+2e^- \rightarrow \text{Cu(s)}; overall Cd(s)+Cu2+(aq)→Cd2+(aq)+Cu(s)\text{Cd(s)}+\text{Cu}^{2+}\text{(aq)} \rightarrow \text{Cd}^{2+}\text{(aq)}+\text{Cu(s)}. …

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