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Choose the Best Answer · Q22

Q.Which of the following relations is correct for the degree of hydrolysis of ammonium acetate?

a) h=KhCh = \sqrt{\dfrac{K_h}{C}}
b) h=KaKbh = \sqrt{\dfrac{K_a}{K_b}}
c) h=KwKa.Kbh = \sqrt{\dfrac{K_w}{K_a.K_b}}
d) h=Ka.KbKwh = \dfrac{K_a.K_b}{K_w}
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Step 1. For a salt of a weak acid AND a weak base, Ka⋅Kb⋅Kh=KwK_a\cdot K_b\cdot K_h=K_w, so Kh=KwKaKbK_h=\dfrac{K_w}{K_a K_b}.

Step 2. For this doubly-hydrolysing case, the degree of hydrolysis relates to KhK_h simply as h=Khh=\sqrt{K_h} (unlike the single-hydrolysis cases, where Kh=h2CK_h=h^2C still involves concentration).

Step 3. Substituting: h=Kh=KwKaKbh=\sqrt{K_h}=\sqrt{\dfrac{K_w}{K_a K_b}}. …

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