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Choose the Best Answer · Q6

Q.Which will make a basic buffer?

a) 50 mL of 0.1M NaOH + 25 mL of 0.1M CH3COOHCH_3COOH
b) 100 mL of 0.1M CH3COOHCH_3COOH + 100 mL of 0.1M NH4OHNH_4OH
c) 100 mL of 0.1M HCl + 200 mL of 0.1M NH4OHNH_4OH
d) 100 mL of 0.1M HCl + 100 mL of 0.1M NaOH
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Step 1. A basic buffer needs a weak base and its salt (its conjugate acid) present TOGETHER after mixing -- so look for a case where the limiting reagent is fully consumed, leaving excess weak base plus the salt formed.

Step 2 (option a). NaOH = 5 mmol, CH3COOHCH_3COOH = 2.5 mmol. All acid consumed, 2.5 mmol NaOH left over with 2.5 mmol CH3COONaCH_3COONa formed -- excess strong base + salt, not a genuine buffer pair.

Step 3 (option b). CH3COOHCH_3COOH = 10 mmol = NH4OHNH_4OH = 10 mmol: exact neutralisation to CH3COONH4CH_3COONH_4 (a weak acid-weak base salt), no excess of either component -- not a buffer. …

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