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Q.The concentration of hydroxide ion in a water sample is found to be 2.5×10−62.5 \times 10^{-6} M. Identify the nature of the solution.

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Step 1. pOH=−log⁡10(2.5×10−6)=6−log⁡102.5=6−0.398=5.602pOH=-\log_{10}(2.5\times10^{-6})=6-\log_{10}2.5=6-0.398=5.602.

Step 2. pH=14−pOH=14−5.602=8.398≈8.40pH=14-pOH=14-5.602=8.398\approx8.40. …

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