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Choose the Best Answer · Q13

Q.C6H5NO2 --Fe/HCl--> A --NaNO2/HCl, 273 K--> B --H2O, 283 K--> C. 'C' is

a) C6H5-OH
b) C6H5-CH2OH
c) C6H5-CHO
d) C6H5-NH2
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Step 1. C6H5NO2 + Fe/HCl reduces the nitro group to the primary amine: A = aniline (C6H5-NH2).

Step 2. A + NaNO2/HCl at 273 K is diazotisation of the aromatic primary amine, giving B = benzenediazonium chloride (C6H5-N2+Cl-), stable only briefly at this low temperature. …

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