Choose the Best Answer · Q19
Q.When ethyl nitrite (CH3CH2-O-N=O) is reduced with Sn / HCl, the pair of compounds formed are
a) ethanol, hydroxylamine hydrochloride
b) ethanol, ammonium hydroxide
c) ethanol, N2H4 (hydrazine)
d) ethylamine, water
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Start your 14-day free trial to unlock the full solution →Step 1. Ethyl nitrite, CH3CH2-O-N=O, is the ESTER-like alkyl nitrite (nitrogen bonded through oxygen), not a nitroalkane (nitrogen bonded directly to carbon) -- so its reduction chemistry is genuinely different from a nitroalkane's stepwise nitro-to-amine ladder.
Step 2. The unit's own stated reaction is: ethyl nitrite + 6[H] (Sn/HCl) gives ethanol + NH3 + H2O -- the O-N bond is cleaved, releasing the alkyl portion as the alcohol and the nitrogen portion (after full reduction) as ammonia. …
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