Choose the Best Answer · Q16
Q.Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules? (NEET)
(a) Br2 > I2 > F2 > Cl2
(b) F2 > Cl2 > Br2 > I2
(c) I2 > Br2 > Cl2 > F2
(d) Cl2 > Br2 > F2 > I2
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Start your 14-day free trial to unlock the full solution →Step 1. List the approximate bond dissociation enthalpies (kJ/mol).
F2 ≈ 159; Cl2 ≈ 242; Br2 ≈ 193; I2 ≈ 151.
Step 2. Rank them.
Cl2 (242) > Br2 (193) > F2 (159) > I2 (151).
Step 3. Explain the anomaly.
A naive expectation (based purely on bond length increasing down the group) would predict F2 to have the strongest bond, but fluorine's very small atomic size causes strong lone-pair-lone-pair repulsion across the short F-F bond, weakening it well below what its bond length alone would suggest — so fluorine's bond is even weaker than bromine's, despite fluorine being a s …
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