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Choose the Best Answer · Q3

Q.An element belongs to group 15 and 3rd period of the periodic table, its electronic configuration would be

(a) 1s2 2s2 2p4
(b) 1s2 2s2 2p3
(c) 1s2 2s2 2p6 3s2 3p2
(d) 1s2 2s2 2p6 3s2 3p3
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✓ Free question

Step 1. Identify the element.

Group 15 elements have the outer configuration ns2 np3. An element in the 3rd period has its outermost electrons in the n = 3 shell, so its configuration must end in 3s2 3p3. This is phosphorus, atomic number 15.

Step 2. Write phosphorus's full electron configuration.

Filling the shells in order for 15 electrons: 1s2 (2) + 2s2 (2) + 2p6 (6) + 3s2 (2) + 3p3 (3) = 2+2+6+2+3 = 15 electrons total, matching Z = 15.

Step 3. Eliminate the distractors.

(a) 1s2 2s2 2p4 is oxygen (Z=8, Group 16, period 2) — wrong group and period. (b) 1s2 2s2 2p3 is nitrogen (Z=7, Group 15 but period 2, not period 3). (c) 1s2 2s2 2p6 3s2 3p2 is silicon (Z=14, Group 14, period 3) — right period but wrong group (np2, not np3).

✓Final answer

(d) — 1s2 2s2 2p6 3s2 3p3, the configuration of phosphorus (Z = 15).

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