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Q.Derive an expression for electrostatic potential due to an electric dipole. OR What is Fibre Optic Communication ? Write its merits and demerits.

Puducherry TnboardTamil Nadu HSC (DGE) Board 2026Subjective· 5mImportance★★★★★
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(a) Superposing the potentials of a dipole's two point charges and simplifying for r≫ar\gg a gives V=14πε0pcos⁡θr2V=\dfrac{1}{4\pi\varepsilon_0}\dfrac{p\cos\theta}{r^2}; (b) fibre optic communication offers huge bandwidth and interference immunity but is fragile and requires precision installation. Both alternatives answered below.

(a) Electrostatic potential due to an electric dipole

1. Setup. A dipole has charges −q-q at A and +q+q at B, separated by 2a2a, dipole moment p=q(2a)p=q(2a). Consider a general point P at distance rr from the dipole's centre O, where the line OP makes angle θ\theta with the dipole axis (from −q-q to +q+q).

2. Potential from each charge (using the cosine rule for distances, and the far-field/short-dipole approximation r≫ar\gg a):

r1≈r−acos⁡θ (distance to +q),r2≈r+acos⁡θ (distance to −q)r_1 \approx r - a\cos\theta \ (\text{distance to } +q), \qquad r_2 \approx r + a\cos\theta \ (\text{distance to } -q)

3. Net potential (superposition, potential is scalar):

V=14πε0[qr1−qr2]=q4πε0[1r−acos⁡θ−1r+acos⁡θ]V = \dfrac{1}{4\pi\varepsilon_0}\left[\dfrac{q}{r_1} - \dfrac{q}{r_2}\right] = \dfrac{q}{4\pi\varepsilon_0}\left[\dfrac{1}{r-a\cos\theta}-\dfrac{1}{r+a\cos\theta}\right]

4. Simplifying (combine over common denominator, then use r≫ar\gg a so r2−a2cos⁡2θ≈r2r^2-a^2\cos^2\theta\approx r^2):

V=q4πε0⋅2acos⁡θr2−a2cos⁡2θ≈14πε0(2aq)cos⁡θr2=14πε0pcos⁡θr2V = \dfrac{q}{4\pi\varepsilon_0}\cdot\dfrac{2a\cos\theta}{r^2-a^2\cos^2\theta} \approx \dfrac{1}{4\pi\varepsilon_0}\dfrac{(2aq)\cos\theta}{r^2} = \dfrac{1}{4\pi\varepsilon_0}\dfrac{p\cos\theta}{r^2}

5. Special cases: on the axial line (θ=0\theta=0), V=14πε0pr2V=\dfrac{1}{4\pi\varepsilon_0}\dfrac{p}{r^2}; on the equatorial line (θ=90°\theta=90°), V=0V=0.

(b) Fibre Optic Communication (FOC)

Principle. Information (voice, data, video), converted to a modulated light signal, is transmitted along a thin glass or plastic fibre. The fibre's core has a slightly higher refractive index than its surrounding cladding, so light entering within the acceptance angle undergoes repeated total internal reflection at the core-cladding boundary, guiding the light along the fibre's length over very long distances with minimal loss.

Merits

  1. Enormous bandwidth/information-carrying capacity, since optical frequencies are far higher than radio/microwave frequencies.
  2. Immune to electromagnetic interference -- unaffected by nearby power lines, radio signals, or lightning (since it carries light, not electric current). …

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