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I. Multiple Choice Questions · Q4

Q.A circular coil of radius 5 cm and 50 turns carries a current of 3 ampere. The magnetic dipole moment of the coil is nearly

(a) 1.0 A m2^2
(b) 1.2 A m2^2
(c) 0.5 A m2^2
(d) 0.8 A m2^2
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Step 1. The magnetic moment of an NN-turn current loop of area AA is pm=NIAp_m=NIA (§3.8.5).

Step 2. The coil's area is A=πR2=π(0.05 m)2=π(0.0025) m2≈0.007854 m2A=\pi R^2 = \pi(0.05\ \text{m})^2 = \pi(0.0025)\ \text{m}^2 \approx 0.007854\ \text{m}^2. …

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