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Question 163 of 199

Q.The radius of curvature of curved surface at a thin planoconvex lens is 10 cm and the refractive index is 1.5. If the plane surface is silvered then the focal length will be :

(a) 20 cm
(b) 5 cm
(c) 10 cm
(d) 15 cm
Puducherry TnboardTamil Nadu HSC (DGE) Board 2020MCQ· 1mImportance★★★★★
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Finding flens=20f_{lens}=20 cm from the lens maker's formula, then combining it as an equivalent silvered-mirror system (F=flens/2F=f_{lens}/2 for a silvered plane face) gives F=10F=10 cm.

Working

Step 1 — focal length of the planoconvex lens alone. Lens maker's formula:

1flens=(n−1)(1R1−1R2)\dfrac1{f_{lens}}=(n-1)\left(\dfrac1{R_1}-\dfrac1{R_2}\right)

Here the curved surface has R1=+10R_1=+10 cm and the plane surface has R2=∞R_2=\infty:

1flens=(1.5−1)(110−0)=0.5×0.1=0.05 cm−1 ⇒ flens=20 cm\dfrac1{f_{lens}}=(1.5-1)\left(\dfrac1{10}-0\right)=0.5\times0.1=0.05\ \text{cm}^{-1}\ \Rightarrow\ f_{lens}=20\ \text{cm}

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