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Miscellaneous Exercise · Q1

Q.If a parabolic reflector is 2020 cm in diameter and 55 cm deep, find the focus.

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✓ Free question

Place the vertex at the origin with the parabola opening upward; use the rim point (10,5)(10, 5) to find a=5a = 5 in x2=4ayx^2 = 4ay, giving the focus at (0,5)(0, 5) — 5 cm from the vertex.


A parabolic reflector has a beautiful property: all rays parallel to its axis reflect through a single point, the focus. To find where that point sits, we need to translate the physical dimensions into the standard equation of a parabola.

The natural coordinate system places the vertex at the origin with the parabola opening upward (or along the positive yy-axis). The standard form is then

x2=4ayx^2 = 4ay

where the focus sits at (0,a)(0, a) and the directrix is the line y=−ay = -a. The parameter aa measures the distance from the vertex to the focus.

Now we extract a point on the parabola from the given dimensions. The reflector is 2020 cm in diameter, so the rim extends 1010 cm on either side of the axis. At that horizontal distance x=10x = 10 cm, the depth is 55 cm, meaning y=5y = 5 cm. The point (10,5)(10, 5) lies on the parabola.


Finding the focus:

  1. Substitute the rim point into the standard equation. We have x=10x = 10 and y=5y = 5:

102=4a⋅510^2 = 4a \cdot 5

100=20a100 = 20a

  1. Solve for aa.

a=10020=5a = \frac{100}{20} = 5

  1. Locate the focus. The focus is at (0,a)=(0,5)(0, a) = (0, 5) in our coordinate system, which means it sits 55 cm above the vertex along the axis of symmetry.
Tip

For any parabolic dish, if the diameter is DD and depth is dd, the focus lies at distance a=D216da = \frac{D^2}{16d} from the vertex. Here, a=20216⋅5=40080=5a = \frac{20^2}{16 \cdot 5} = \frac{400}{80} = 5 cm.

Watch out

Don't confuse the depth (vertical distance from vertex to rim) with the focal length. The depth tells you a point on the curve; the focal length aa is what you solve for.


✓Final answer

The focus is 5 cm from the vertex (at the point (0,5)(0, 5) when the vertex is at the origin).

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