Skip to content
Question of 135

Q.(a) Why phenols are acidic in nature ?

(b) Explain the mechanism of the following reaction : C2H5OH --(Conc. H2SO4, 443 K)--> CH2=CH2 + H2O
Punjab PsebPSEB Punjab Class 12 Board 2018Subjective· 4mImportance★★★★★
0% · 0/135 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

(a) Phenol is acidic mainly because its conjugate base (the phenoxide ion) is resonance-stabilised by the ring, unlike an alkoxide from an alcohol. (b) Ethanol's acid-catalysed dehydration to ethene proceeds by protonation of –OH, loss of water to form a carbocation, then loss of a β\beta-H to give the alkene.

(a) Why phenols are acidic:

In phenol, the −OH-OH group is attached directly to an sp2sp^2 aromatic carbon. When phenol loses a proton, it forms the phenoxide ion, C6H5O−C_6H_5O^-. The negative charge on this oxygen is delocalised into the benzene ring by resonance (the O lone pair overlaps with the ring's π\pi system, spreading negative charge to the ortho and para ring carbons), giving several stabilised resonance structures. This resonance stabilisation of the conjugate base lowers its energy and favours the forward ionisation (C6H5OH⇌C6H5O−+H+C_6H_5OH \rightleftharpoons C_6H_5O^- + H^+), making phenol distinctly acidic (unlike alcohols, whose alkoxide ion, RO−RO^-, has no such ring to delocalise into, and is destabilised further by the electron-donating alkyl group). This is why phenol reacts with NaOHNaOH (unlike alcohols) though it is still a much weaker acid than carboxylic acids.

(b) Mechanism of acid-catalysed dehydration of ethanol (E1):

C2H5OH→443 KConc. H2SO4CH2=CH2+H2OC_2H_5OH \xrightarrow[443\,K]{\text{Conc. } H_2SO_4} CH_2=CH_2 + H_2O

Step 1 — Protonation: The oxygen of ethanol is protonated by H2SO4H_2SO_4, converting the poor leaving group −OH-OH into a good one, forming a protonated (oxonium) intermediate:

CH3CH2−OH+H+→CH3CH2−OH2+CH_3CH_2-OH + H^+ \rightarrow CH_3CH_2-OH_2^+

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.