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Q.(a) Write Reimer-Tiemann's reaction.

(b) How will you convert Chlorobenzene to Phenol ?
(c) Why Phenols are more acidic than Alcohol ?
Punjab PsebPSEB Punjab Class 12 Board 2019Subjective· 4mImportance★★★★★
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Reimer-Tiemann formylates phenol at the ortho position; Dow's process converts chlorobenzene to phenol under forcing conditions; phenol's greater acidity comes from resonance stabilisation of the phenoxide ion.

  1. Reimer-Tiemann reaction: Phenol is treated with chloroform and aqueous NaOH at about 340 K, then the intermediate is hydrolysed. Dichlorocarbene (:CCl2:\text{CCl}_2), generated from CHCl3_3 + NaOH, attacks the phenoxide ring, ultimately introducing a -CHO group at the position ortho to -OH: C6H5OH+CHCl3+3NaOH→340Ko-HOC6H4CHO (salicylaldehyde)+3NaCl+2H2O\text{C}_6\text{H}_5\text{OH} + \text{CHCl}_3 + 3\text{NaOH} \xrightarrow{340\text{K}} o\text{-HOC}_6\text{H}_4\text{CHO (salicylaldehyde)} + 3\text{NaCl} + 2\text{H}_2\text{O}
  2. Chlorobenzene to phenol (Dow's process): Chlorobenzene is fused with aqueous NaOH at 623 K under a high pressure of 320 atm, giving sodium phenoxide, which is then acidified to give phenol: C6H5Cl+2NaOH→623K, 320 atmC6H5ONa+NaCl+H2O\text{C}_6\text{H}_5\text{Cl} + 2\text{NaOH} \xrightarrow{623\text{K},\ 320\ \text{atm}} \text{C}_6\text{H}_5\text{ONa} + \text{NaCl} + \text{H}_2\text{O} C6H5ONa+HCl→C6H5OH+NaCl\text{C}_6\text{H}_5\text{ONa} + \text{HCl} \rightarrow \text{C}_6\text{H}_5\text{OH} + \text{NaCl} …

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