Q.An organism has two pair of chromosomes (i.e., chromosome number = 4). Diagrammatically represent the chromosomal arrangement during different phases of meiosis-II.
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Start your 14-day free trial to unlock the full solution →For an organism with chromosome number 4 (two homologous pairs), meiosis I has already reduced each cell to 2 (still double-stranded) chromosomes; meiosis II then simply separates the sister chromatids of those 2 chromosomes at each of its four stages, ending in four haploid cells of 2 chromosomes each.
A text description of the arrangement at each stage, in place of a drawing, is given below, tracking a single cell as it passes through meiosis II.
Before meiosis II begins, meiosis I has already taken the original diploid cell (chromosome number 4, i.e. two homologous pairs) through pairing, crossing over and the separation of homologues, producing two dyad cells, each now haploid with a chromosome number of 2 — but each of those 2 chromosomes is still made up of two sister chromatids joined at one centromere, since only the homologues, not the chromatids, were separated in meiosis I.
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Prophase II. Each cell carries 2 chromosomes, each still a two-chromatid structure. Unlike prophase I, there is no pairing of homologues here, since each cell now holds only one member of what was originally each homologous pair. The chromosomes condense once again, and by the end of this stage the nuclear membrane disappears, much as in an ordinary mitotic prophase.
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Metaphase II. The 2 (still double-stranded) chromosomes line up individually along the equator of the cell, at the metaphase plate. Microtubules from the two opposite spindle poles attach to the kinetochores of the sister chromatids of each chromosome — this time it is the two chromatids of a single chromosome that are gripped by fibres from opposite poles, rather than two homologues as in metaphase I. …
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