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Q.Find the mean deviation about the mean for the following data— Marks Obtained: 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80; Number of Students: 2, 3, 8, 14, 8, 3, 2 OR Calculate the mean, variance and standard deviation for the following distribution— Class: 30-40, 40-50, 50-60, 60-70, 70-80, 80-90, 90-100; Frequency: 3, 7, 12, 15, 8, 3, 2

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2024Subjective· 5mImportance★★★★★
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The mean deviation about the mean for the given distribution is 1010 (the primary alternative of this OR question is answered).

Using class midpoints xix_i: 15,25,35,45,55,65,7515,25,35,45,55,65,75 with frequencies fif_i: 2,3,8,14,8,3,22,3,8,14,8,3,2 (total N=40N=40).

First find the mean xˉ=∑fixiN\bar x=\dfrac{\sum f_ix_i}{N}:

∑fixi=2(15)+3(25)+8(35)+14(45)+8(55)+3(65)+2(75)\sum f_ix_i=2(15)+3(25)+8(35)+14(45)+8(55)+3(65)+2(75)

=30+75+280+630+440+195+150=1800=30+75+280+630+440+195+150=1800

xˉ=180040=45\bar x=\dfrac{1800}{40}=45

Now find ∣xi−xˉ∣|x_i-\bar x| for each class: 30,20,10,0,10,20,3030,20,10,0,10,20,30 respectively, and multiply by fif_i:

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