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Worked Examples · Example 4.6

Q.Consider a tightly wound 100100 turn coil of radius 10 cm10\ \text{cm}, carrying a current of 1 A1\ \text{A}. What is the magnitude of the magnetic field at the centre of the coil?

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The magnetic field at the centre of a circular coil is given by B=μ0NI2RB = \frac{\mu_0 N I}{2R}. For N=100N = 100, I=1 AI = 1\ \text{A}, R=0.1 mR = 0.1\ \text{m}, the magnitude is 6.28×10−4 T6.28 \times 10^{-4}\ \text{T}.

Why the Biot–Savart Law?

The magnetic field at the centre of a current-carrying circular loop arises from the Biot–Savart law. Each tiny current element I dl⃗I\,d\vec{l} on the loop produces a magnetic field at the centre that points along the axis (perpendicular to the plane of the loop). Because of symmetry, the contributions from all elements add constructively -- there is no cancellation. The key insight: every element is at the same distance RR from the centre, and the angle between dl⃗d\vec{l} and the radial vector is always 90∘90^\circ, so the cross product simplifies beautifully.

B=μ0NI2RB = \frac{\mu_0 N I}{2R}

This is the central result for a tightly wound coil of NN turns. Let's derive it step by step.

Step-by-step solution

  1. Start with a single turn. For a single circular loop of radius RR, carrying current II, the magnetic field at the centre is

B1=μ0I2RB_1 = \frac{\mu_0 I}{2R}

This comes from integrating the Biot–Savart law: each element I dlI\,dl contributes dB=μ04πI dlsin⁡θr2dB = \frac{\mu_0}{4\pi} \frac{I\,dl \sin\theta}{r^2}. Here r=Rr = R and θ=90∘\theta = 90^\circ (since dl⃗d\vec{l} is tangent and the vector from element to centre is radial), so sin⁡θ=1\sin\theta = 1. The integral ∮dl=2πR\oint dl = 2\pi R gives the result.

  1. Account for multiple turns. The coil has N=100N = 100 turns, all tightly wound so they essentially occupy the same radius RR. The fields from each turn add linearly (superposition). Hence

B=N⋅B1=μ0NI2RB = N \cdot B_1 = \frac{\mu_0 N I}{2R}

  1. Plug in the numbers.

    • μ0=4π×10−7 T⋅m/A\mu_0 = 4\pi \times 10^{-7}\ \text{T·m/A}
    • N=100N = 100
    • I=1 AI = 1\ \text{A}
    • R=10 cm=0.1 mR = 10\ \text{cm} = 0.1\ \text{m}

    So …

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