Question 54 of 62
Q.What would be the IUPAC name for an element with atomic number 222 ?
(a) didibium
(b) bibibiium
(c) bibibium
(d) bididium
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2023MCQ· 1mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →IUPAC's systematic element-naming convention assigns a root to each digit (0=nil, 1=un, 2=bi, 3=tri, 4=quad, 5=pent, 6=hex, 7=sept, 8=oct, 9=enn), strings them together in atomic-number order, and adds the ending '-ium'.
For atomic number 222, the digits are 2, 2, 2. The IUPAC numerical root for the digit 2 is "bi". Concatenating the three roots in order gives "bi-bi-bi", and adding the standard ending "-ium" gives "bibibiium" before applying IUPAC's elision rule.
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