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Choose the Best Answer · Q1

Q.Electronic configuration of species M2+^{2+} is 1s2^2 2s2^2 2p6^6 3s2^2 3p6^6 3d6^6 and its atomic weight is 56. The number of neutrons in the nucleus of species M is

(a) 26
(b) 22
(c) 30
(d) 24
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✓ Free question

Step 1. Add up the electrons shown in the given configuration of M2+^{2+}: 1s2 2s2 2p6 3s2 3p6 3d6=2+2+6+2+6+6=241s^2\,2s^2\,2p^6\,3s^2\,3p^6\,3d^6=2+2+6+2+6+6=24 electrons.

Step 2. M2+^{2+} has lost 2 electrons relative to neutral M, so neutral M has 24+2=2624+2=26 electrons, i.e. atomic number Z=26Z=26 (this is iron, Fe).

Step 3. Number of neutrons = atomic weight − atomic number =56−26=30=56-26=30.

Step 4. This matches option (c). Option (a) 26 is just the atomic number itself (a common slip); (b) and (d) don't correspond to a consistent proton/neutron split for mass number 56.

✓Final answer

(c) 30

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