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Choose the Best Answer · Q2

Q.The energy of light of wavelength 45 nm is

(a) 6.67×10156.67\times10^{15} J
(b) 6.67×10116.67\times10^{11} J
(c) 4.42×10−184.42\times10^{-18} J
(d) 4.42×10−154.42\times10^{-15} J
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✓ Free question

Step 1. Photon energy is E=hc/λE=hc/\lambda, with h=6.626×10−34h=6.626\times10^{-34} J s, c=3×108c=3\times10^8 m/s, and λ=45 nm=45×10−9\lambda=45\ \text{nm}=45\times10^{-9} m.

Step 2. E=(6.626×10−34)(3×108)45×10−9=1.988×10−254.5×10−8≈4.42×10−18 JE=\frac{(6.626\times10^{-34})(3\times10^8)}{45\times10^{-9}}=\frac{1.988\times10^{-25}}{4.5\times10^{-8}}\approx4.42\times10^{-18}\ \text{J}

Step 3. This matches option (c). Options (a) and (b) are far too large by many orders of magnitude (a unit-conversion slip, e.g. forgetting the nm-to-m conversion); (d) is off by a factor of 100 from a decimal-point error.

✓Final answer

(c) 4.42×10−184.42\times10^{-18} J

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