An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electr

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Q. An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons, find the symbol of the ion.

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Step 1. Let $p$ = number of protons. Since the ion carries a unit NEGATIVE charge, it has one more electron than protons: electrons $=p+1$ .

Step 2. Neutrons = mass number − protons $=37-p$ .

Step 3. Given "11.1% more neutrons than electrons": $37-p=1.111\times(p+1)$

Step 4. Solve: $37-p=1.111p+1.111\ \Rightarrow\ 37-1.111=1.111p+p\ \Rightarrow\ 35.889=2.111p\ \Rightarrow\ p\approx17$ . …

Q.An ion with mass number 37 possesses unit negative charge. If the ion contains 11.1% more neutrons than electrons, find the symbol of the ion.