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Choose the Best Answer · Q3

Q.The energies E1E_1 and E2E_2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e. λ1\lambda_1 and λ2\lambda_2 will be

(a) λ1λ2=1\dfrac{\lambda_1}{\lambda_2}=1
(b) λ1=2λ2\lambda_1=2\lambda_2
(c) λ1=25×50 λ2\lambda_1=\sqrt{25\times50}\,\lambda_2
(d) 2λ1=λ22\lambda_1=\lambda_2
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✓ Free question

Step 1. From E=hc/λE=hc/\lambda, wavelength and energy are inversely proportional: λ∝1/E\lambda\propto1/E.

Step 2. So λ1λ2=E2E1=5025=2\dfrac{\lambda_1}{\lambda_2}=\dfrac{E_2}{E_1}=\dfrac{50}{25}=2, i.e. λ1=2λ2\lambda_1=2\lambda_2.

Step 3. This matches option (b). Option (a) would require E1=E2E_1=E_2, which is not given; option (c) proposes λ1=25×50 λ2\lambda_1=\sqrt{25\times50}\,\lambda_2, an arbitrary combination with no basis in E=hc/λE=hc/\lambda; option (d) inverts the correct ratio.

✓Final answer

(b) λ1=2λ2\lambda_1=2\lambda_2

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