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Exercise 12.5 · Q12

Q.A bag contains 6 green, 2 white, and 7 black balls. If two balls are drawn simultaneously, then the probability that both are of different colours is

(1) 68105\dfrac{68}{105}
(2) 71105\dfrac{71}{105}
(3) 64105\dfrac{64}{105}
(4) 73105\dfrac{73}{105}
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Step 1. Given. 6+2+7=156+2+7=15 balls; choose 2: n(S)=(152)=105n(S)=\binom{15}2=105.

Step 2. Same-colour count. (62)+(22)+(72)=15+1+21=37\binom62+\binom22+\binom72=15+1+21=37. …

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