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Exercise 12.5 · Q15

Q.A number xx is chosen at random from the first 100 natural numbers. Let AA be the event of numbers which satisfy (x−10)(x−50)x−30≥0\dfrac{(x-10)(x-50)}{x-30}\ge 0. Then P(A)P(A) is

(1) 0.200.20
(2) 0.510.51
(3) 0.710.71
(4) 0.700.70
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Step 1. Critical points. f(x)=(x−10)(x−50)x−30f(x)=\dfrac{(x-10)(x-50)}{x-30} changes sign (or is undefined) at x=10,30,50x=10,30,50.

Step 2. Sign chart. For x<10x<10: negative. For 10<x<3010<x<30: positive. For 30<x<5030<x<50: negative. For x>50x>50: positive. At x=10,50x=10,50: f=0f=0 (included, since ≥0\ge0); at x=30x=30: undefined (excluded). …

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