Skip to content
Exercise 12.5 · Q23

Q.Ten coins are tossed. The probability of getting at least 8 heads is

(1) 764\dfrac{7}{64}
(2) 732\dfrac{7}{32}
(3) 716\dfrac{7}{16}
(4) 7128\dfrac{7}{128}
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
63% · 56/89 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Total outcomes. n(S)=210=1024n(S)=2^{10}=1024.

Step 2. Favourable -- at least 8 heads. (108)+(109)+(1010)=45+10+1=56\binom{10}8+\binom{10}9+\binom{10}{10}=45+10+1=56. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.