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Exercise 12.5 · Q6

Q.Two items are chosen from a lot containing twelve items of which four are defective. The probability that at least one of the items is defective is

(1) 1933\dfrac{19}{33}
(2) 1733\dfrac{17}{33}
(3) 2333\dfrac{23}{33}
(4) 1333\dfrac{13}{33}
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Step 1. Given. 12 items, 4 defective, 8 good. Choose 2: n(S)=(122)=66n(S)=\binom{12}{2}=66.

Step 2. Complement -- no defectives. Both good: (82)=28\binom82=28 ways. P(none defective)=2866=1433P(\text{none defective})=\dfrac{28}{66}=\dfrac{14}{33}. …

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