Question 63 of 71
Q.What is the relation between the average kinetic energy and pressure?
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2024Subjective· 3mImportance★★★★★
89% · 63/71 Questions
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Start your 14-day free trial to unlock the full solution →From the kinetic theory expression PV = (1/3) N m v_rms^2, one can show that PV = (2/3) times the total average translational kinetic energy of the gas molecules.
From the kinetic theory of gases, the pressure exerted by a gas of N molecules, each of mass m, in a volume V is:
P = (1/3) (N/V) m v_rms^2
Multiplying both sides by V:
PV = (1/3) N m v_rms^2
The average translational kinetic energy per molecule is:
KE_avg = (1/2) m v_rms^2
So m v_rms^2 = 2 KE_avg. Substituting:
PV = (1/3) N (2 KE_avg) = (2/3) N KE_avg
Or, dividing by V:
P = (2/3) (N/V) KE_avg = (2/3) × (average kinetic energy per unit volume)
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