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Question 69 of 71

Q.If the internal energy of an ideal gas U and volume V are doubled, then the pressure:

(a) halves
(b) doubles
(c) increases four times
(d) remains same
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2026MCQ· 1mImportance★★★★★
97% · 69/71 Questions
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Since U is proportional to T for an ideal gas, doubling U doubles T; combined with V also doubling, the pressure P = mu*RT/V is unchanged because the factor of 2 in T is exactly cancelled by the factor of 2 in V.

For an ideal gas (fixed number of moles mu), the internal energy is

U = (f/2)muR*T

where f is the number of degrees of freedom. This shows U is directly proportional to the absolute temperature T.

Step 1: If U becomes 2U, then since U is proportional to T, the temperature must also become 2T (with mu and f unchanged).

Step 2: The ideal gas equation is PV = muRT, so P = muRT/V.

Step 3: With the new values T' = 2T and V' = 2V,

P' = muR(2T)/(2V) = muRT/V = P (unchanged)

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