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V. Numerical Problems · Q2

Q.A spider of mass 50 g50\text{ g} is hanging at rest on a single vertical thread of a cobweb, as shown in the figure. What is the tension in the thread?

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Figure — a spider of mass 50 g hanging from a single vertical thread, with tension and weight marked — Class 12 Physics question
Figurea spider of mass 50 g hanging from a single vertical thread, with tension and weight marked — Class 12 Physics question

Step 1. The spider (mass m=50 g=0.05 kgm=50\text{ g}=0.05\text{ kg}) hangs in equilibrium on a single vertical thread, so only two forces act on it: gravity (mg, downward) and the string tension T (upward).

Step 2. Since the spider is at rest, acceleration is zero, so by Newton's second law the net force is zero: T−mg=0⇒T=mgT-mg=0\Rightarrow T=mg.

Step 3. Substituting: T=0.05 kg×9.8 m s−2=0.49 NT=0.05\text{ kg}\times9.8\text{ m s}^{-2}=0.49\text{ N}.

✓Final answer

T=0.49 NT=0.49\text{ N}.

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