Q.(a) Explain the horizontal oscillations of a spring. OR
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →A block of mass m on a spring of force constant k, oscillating horizontally on a smooth surface, obeys Hooke's law (F = -kx); applying Newton's second law to this restoring force shows the motion is SHM with time period T = 2π√(m/k).
Setup: A block of mass m is attached to one end of a massless spring of force constant k; the other end of the spring is fixed to a wall, and the block rests on a smooth (frictionless) horizontal surface. In equilibrium, the spring is at its natural length. The block is displaced by a small distance x from this equilibrium position and released.
Restoring force: By Hooke's law, when the spring is stretched or compressed by x, it exerts a restoring force on the block, proportional to x and directed back toward the equilibrium position:
F = −kx
(the negative sign shows the force always opposes the displacement)
Applying Newton's second law (F = ma, with a = d²x/dt²):
m (d²x/dt²) = −kx
d²x/dt² = −(k/m) x
This is exactly the standard SHM differential equation, d²x/dt² = −ω²x, with:
ω² = k/m, i.e., ω = √(k/m)
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.