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Exercise 4.6 · Q19

Q.If sin⁡−1x5+cosec−154=π2\sin^{-1}\dfrac{x}5 + \text{cosec}^{-1}\dfrac54 = \dfrac{\pi}2, then the value of xx is

(1) 44
(2) 55
(3) 22
(4) 33
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Rewriting the cosecant-inverse term as a sine-inverse term of the reciprocal directly isolates sin⁡−1(x/5)\sin^{-1}(x/5) as the complement of sin⁡−1(4/5)\sin^{-1}(4/5), which (via a 33–44–55 triangle) equals cos⁡−1(4/5)\cos^{-1}(4/5) — giving x/5=3/5x/5=3/5.

Step 1. Convert the cosecant-inverse term. cosec−154=sin⁡−1(15/4)=sin⁡−145\text{cosec}^{-1}\dfrac54=\sin^{-1}\left(\dfrac1{5/4}\right)=\sin^{-1}\dfrac45.

Step 2. Substitute and isolate. sin⁡−1x5+sin⁡−145=π2⇒sin⁡−1x5=π2−sin⁡−145\sin^{-1}\dfrac x5+\sin^{-1}\dfrac45=\dfrac{\pi}2\Rightarrow\sin^{-1}\dfrac x5=\dfrac{\pi}2-\sin^{-1}\dfrac45. …

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