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Exercise 4.6 · Q9

Q.If x=15x = \dfrac15, the value of cos⁡(cos⁡−1x+2sin⁡−1x)\cos\left(\cos^{-1}x + 2\sin^{-1}x\right) is

(1) −2425-\sqrt{\dfrac{24}{25}}
(2) 2425\sqrt{\dfrac{24}{25}}
(3) 15\dfrac15
(4) −15-\dfrac15
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Splitting one of the two sin⁡−1x\sin^{-1}x copies to pair with cos⁡−1x\cos^{-1}x turns the angle into π2+sin⁡−1x\dfrac{\pi}2+\sin^{-1}x, and the cosine of that reduces to −sin⁡(sin⁡−1x)=−x-\sin(\sin^{-1}x)=-x directly.

Step 1. Split the angle. cos⁡−1x+2sin⁡−1x=(cos⁡−1x+sin⁡−1x)+sin⁡−1x=π2+sin⁡−1x\cos^{-1}x+2\sin^{-1}x=\left(\cos^{-1}x+\sin^{-1}x\right)+\sin^{-1}x=\dfrac{\pi}2+\sin^{-1}x. …

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