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Exercise 4.6 · Q7

Q.If cot⁡−1x=2π5\cot^{-1}x = \dfrac{2\pi}5 for some x∈Rx \in \mathbb{R}, the value of tan⁡−1x\tan^{-1}x is

(1) −π10-\dfrac{\pi}{10}
(2) π5\dfrac{\pi}5
(3) π10\dfrac{\pi}{10}
(4) −π5-\dfrac{\pi}5
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Since cot⁡−1x\cot^{-1}x and tan⁡−1x\tan^{-1}x are complementary for the SAME xx, the value of tan⁡−1x\tan^{-1}x follows immediately once cot⁡−1x\cot^{-1}x is known — no need to find xx itself.

Step 1. State the complementary identity. tan⁡−1x+cot⁡−1x=π2\tan^{-1}x+\cot^{-1}x=\dfrac{\pi}2 for every real xx. …

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