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Exercise 10(a) · Q10

Q.From the top of a building 6060 m high, the angles of depression of the top and the bottom of a tower are observed to be 30∘30^\circ and 60∘60^\circ respectively. Find the height of the tower.

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Step 1. Let the tower's height be HH and the horizontal distance between the building and the tower be xx. The angle of depression to the tower's bottom is 60∘60^\circ, and the vertical drop from the building's top (6060 m) to the ground is the full 6060 m, so

tan⁡60∘=60x ⟹ x=603=203 m.\tan60^\circ=\frac{60}{x}\ \Longrightarrow\ x=\frac{60}{\sqrt3}=20\sqrt3\text{ m}. …

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