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Exercise 10(a) · Q3

Q.In △ABC\triangle ABC, if b=6b=6, c=10c=10 and A=120∘A=120^\circ, find the side aa.

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Step 1. SAS data: b=6,c=10,A=120∘b=6,c=10,A=120^\circ. Use

a2=b2+c2−2bccos⁡A.a^2=b^2+c^2-2bc\cos A.

Step 2. Since AA is obtuse, cos⁡120∘=−12\cos120^\circ=-\frac12. Substitute:

a2=62+102−2(6)(10)(−12)=36+100+60.a^2=6^2+10^2-2(6)(10)\left(-\frac12\right)=36+100+60.

Step 3. Simplify:

a2=136+60=196.a^2=136+60=196.

Step 4. Take the positive square root:

a=196=14.a=\sqrt{196}=14.

[!ANSWER] a=14a=14

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