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Exercise 10(a) · Q15

Q.In △ABC\triangle ABC, if a=7a=7, b=8b=8, c=9c=9, find the angle AA.

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Step 1. With all three sides known (a=7,b=8,c=9a=7,b=8,c=9), use the SSS form of the Cosine Rule:

cos⁡A=b2+c2−a22bc.\cos A=\frac{b^2+c^2-a^2}{2bc}.

Step 2. Substitute:

cos⁡A=82+92−722(8)(9)=64+81−49144.\cos A=\frac{8^2+9^2-7^2}{2(8)(9)}=\frac{64+81-49}{144}.

Step 3. Simplify the numerator: 64+81−49=9664+81-49=96. So

cos⁡A=96144=23.\cos A=\frac{96}{144}=\frac23. …

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