Q.In △ABC, if a=5, b=7 and C=60∘, find the side c.
Concept understanding — Cosine Rule
Cosine Rule
The sine rule needs at least one known angle paired with its opposite side to get started. But two very common situations don't offer that: you might know two sides and the angle between them (SAS), or all three sides (SSS) with no angle at all. The Cosine Rule is built exactly for these cases:
cosA=2bcb2+c2−a2,a2=b2+c2−2bccosA,
and cyclically for B and C. Think of it as a generalisation of the Pythagorean theorem: when A=90∘, cosA=0 and the formula collapses to a2=b2+c2 exactly.
Where it comes from
Placing A at the origin with B along the x-axis, the third vertex C sits at (bcosA,bsinA) purely from the definition of angle A and the length AC=b. The distance formula between B=(c,0) and C then expands, via cos2A+sin2A=1, straight into a2=b2+c2−2bccosA — no trigonometric identity beyond the Pythagorean one is needed.
How it is used
- SAS → third side: given b,c,A, compute a directly, then use the sine rule to find B or C (picking the smaller of the two unknown angles avoids the ambiguous-angle trap).
- SSS → any angle: solve the rearranged form for cosA (or B, or C) using all three known sides, then take cos−1.
- A building block: the half-angle formulas, and Heron's formula, are both derived from the cosine rule by combining it with the double-angle identities cosA=1−2sin22A=2cos22A−1.
A common trap
Students often plug values into cosA=2bcb2+c2−a2 but mix up which side is "a" (opposite A) versus which two are the "legs" b,c — since the rule is not symmetric in which side plays the role of a, getting this wrong silently computes the wrong angle. It helps to always read the rule as "(sum of squares of the two sides forming the angle) minus (square of the side facing the angle), over twice their product."
Worked micro-example
For a=7,b=8,c=9: cosA=14464+81−49=14496=32≈0.667, so A≈48.19∘ — a genuinely acute angle, as expected since a is the smallest side.
[!TLDR] Apply the Cosine Rule c2=a2+b2−2abcosC with a=5,b=7,C=60∘.
[!ANSWER] c=39
Step 1. Two sides a=5,b=7 and the included angle C=60∘ are given (SAS), so use
c2=a2+b2−2abcosC.
Step 2. Substitute, with cos60∘=21:
c2=52+72−2(5)(7)(21)=25+49−35.
Step 3. Simplify:
c2=74−35=39.
Step 4. Take the positive square root:
c=39≈6.245.
[!ANSWER] c=39≈6.245
- Solving for the wrong side (e.g. a instead of c), since C is included between a and b, so the formula must give c.
- Sign error when substituting cos60∘.
- Arithmetic slip adding 25+49.
- CBSE 2026Set ANNUAL2 marksQ.In △ABC, prove that a(bcosC−ccosB)=b2−c2.
›Reveal solutionSolution
Substitute cosC and cosB from the cosine rule and simplify.
By the cosine rule:
cosC=2aba2+b2−c2,cosB=2aca2+c2−b2
LHS =a(bcosC−ccosB)=abcosC−accosB
abcosC=ab⋅2aba2+b2−c2=2a2+b2−c2
accosB=ac⋅2aca2+c2−b2=2a2+c2−b2
abcosC−accosB=2a2+b2−c2−2a2+c2−b2=2(a2+b2−c2)−(a2+c2−b2)
=22b2−2c2=b2−c2
Hence a(bcosC−ccosB)=b2−c2 = RHS. Hence proved.
✓Final answerProved: a(bcosC−ccosB)=b2−c2 using the cosine rule.
- CBSE 2023Set ANNUAL2 marksMCQQ.In △ABC, if c2+a2−b2=ac, then ∠B= ________.(a) 4π(b) 3π(c) 2π(d) 6π
›Reveal solutionSolution
Compare with the cosine rule b2=a2+c2−2accosB.
By the cosine rule, b2=a2+c2−2accosB⇒a2+c2−b2=2accosB.
Given c2+a2−b2=ac, so 2accosB=ac⇒cosB=21⇒B=3π.
✓Final answer(b) 3π
- CBSE 2022Set ANNUAL2 marksMCQQ.In △ABC if c2+a2−b2=ac, then ∠B= ________.(a) 4π(b) 3π(c) 2π(d) 6π
›Reveal solutionSolution
Compare with the Cosine Rule formula for cosB.
By the Cosine Rule: cosB=2aca2+c2−b2
Given c2+a2−b2=ac:
cosB=2acac=21⟹B=3π
✓Final answerB=3π (option b)
- CBSE 2017Set ANNUAL2 marksQ.In △ABC, prove that a(bcosC−ccosB)=b2−c2.
›Reveal solutionSolution
Substitute cosB and cosC from the cosine rule and simplify.
By the cosine rule:
cosC=2aba2+b2−c2,cosB=2aca2+c2−b2
a(bcosC−ccosB)=a[b⋅2aba2+b2−c2−c⋅2aca2+c2−b2]
=a[2aa2+b2−c2−2aa2+c2−b2]=21[(a2+b2−c2)−(a2+c2−b2)]
=21[2b2−2c2]=b2−c2
Hence a(bcosC−ccosB)=b2−c2. Hence proved.
✓Final answerProved using the cosine rule: a(bcosC−ccosB)=b2−c2
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