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Q.Transform the equation x+y+1=0x + y + 1 = 0 into normal form.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2018Subjective· 2mImportance★★★★★
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Rearranging so the RHS is positive and dividing by a2+b2\sqrt{a^2+b^2} converts x+y+1=0x+y+1=0 to normal form xcos⁡5π4+ysin⁡5π4=12x\cos\frac{5\pi}{4}+y\sin\frac{5\pi}{4}=\frac{1}{\sqrt2}.

Concept: Normal form of a line

The normal form of a straight line is xcos⁡α+ysin⁡α=px\cos\alpha + y\sin\alpha = p, where p>0p > 0 is the perpendicular distance from the origin to the line and α\alpha is the angle the perpendicular (normal) makes with the positive x-axis.

Step 1: Write with a positive constant on the right

Given x+y+1=0⇒x+y=−1⇒−x−y=1x + y + 1 = 0 \Rightarrow x + y = -1 \Rightarrow -x - y = 1.

Here a=−1a=-1, b=−1b=-1, c=1c=1 (with c>0c>0, as required).

Step 2: Divide by a2+b2\sqrt{a^2+b^2}

a2+b2=(−1)2+(−1)2=2\sqrt{a^2+b^2} = \sqrt{(-1)^2+(-1)^2} = \sqrt{2}

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