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Q.Explain reversible and irreversible process. Describe the working of Carnot's engine. Obtain the expression for the efficiency.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2019Subjective· 8mImportance★★★★★
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A reversible process retraces its path exactly (ideal); an irreversible one cannot (all real ones). Carnot's engine runs a cycle of 2 isothermal + 2 adiabatic reversible steps between a source at T1 and sink at T2, with efficiency eta = 1 - T2/T1 = 1 - Q2/Q1.

Reversible process: A process that can be made to proceed in the reverse direction by an infinitesimal change in conditions, such that both the system and its surroundings are restored exactly to their initial states, with no loss of energy. It must be carried out infinitely slowly (quasi-statically) with no friction or turbulence. It is an ideal process.

Irreversible process: A process that cannot be retraced in the reverse order to bring the system and surroundings back to their original states. All natural, real processes (with friction, sudden expansion, heat flow across finite temperature differences, etc.) are irreversible.

Carnot's engine: It is an ideal heat engine that works between a hot source at temperature T1 and a cold sink at temperature T2, using a working substance (an ideal gas) in a cylinder. Its cycle (the Carnot cycle) consists of four reversible steps:

  1. Isothermal expansion at T1: the gas absorbs heat Q1 from the source and expands.
  2. Adiabatic expansion: the gas expands without heat exchange, its temperature falling from T1 to T2.
  3. Isothermal compression at T2: the gas rejects heat Q2 to the sink while being compressed.
  4. Adiabatic compression: the gas is compressed without heat exchange, its temperature rising from T2 back to T1, completing the cycle.

Efficiency:

The efficiency of a heat engine is:

eta = (work done W) / (heat absorbed Q1) = (Q1 - Q2) / Q1 = 1 - Q2/Q1

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