Q.Dark reaction in photosynthesis is called so because
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The Calvin Cycle: Making Sugar from Thin Air
Plants do something that seems almost magical: they take carbon dioxide — a waste gas we breathe out — and turn it into sugar. The Calvin cycle is the biochemical machine that makes this happen. It runs in the stroma of the chloroplast, the fluid-filled space that surrounds the thylakoid membranes where the light reactions happen.
Think of it this way. The light reactions capture sunlight and produce ATP and NADPH — these are like charged batteries and reducing power. The Calvin cycle uses those batteries to "fix" carbon from CO₂ into organic molecules. No light is directly needed for the cycle itself, which is why it's sometimes called the dark reaction (though it usually runs during the day).
The Big Picture: Three Phases
The Calvin cycle has three distinct phases, and every turn of the cycle is about one thing: taking one molecule of CO₂ and attaching it to a five-carbon sugar called RuBP. The entire cycle must turn six times to produce one molecule of glucose.
Phase 1: Carboxylation — CO₂ is attached to RuBP. This is the entry point for carbon into the biosphere.
Phase 2: Reduction — The fixed carbon is reduced using ATP and NADPH, producing a three-carbon sugar called G3P (glyceraldehyde-3-phosphate).
Phase 3: Regeneration — The remaining carbon skeletons are rearranged to rebuild RuBP, so the cycle can continue.
6 CO2+18 ATP+12 NADPH+12 H2O→C6H12O6+18 ADP+18 Pi+12 NADP+
Phase 1: Carboxylation — The Key Step
The enzyme RuBisCO (Ribulose-1,5-bisphosphate carboxylase-oxygenase) grabs a CO₂ molecule and attaches it to RuBP, a five-carbon sugar with two phosphate groups. The result is an unstable six-carbon intermediate that instantly splits into two molecules of 3-phosphoglycerate (3-PGA).
RuBisCO is the most abundant protein on Earth. It is also notoriously slow and inefficient — it can mistakenly grab O₂ instead of CO₂, leading to photorespiration. This is a major reason why C₄ and CAM plants evolved alternative pathways.
Phase 2: Reduction — Making Sugar
Each 3-PGA molecule now gets phosphorylated by ATP (using one ATP per molecule) to form 1,3-bisphosphoglycerate. Then NADPH donates electrons to reduce this to glyceraldehyde-3-phosphate (G3P) — a three-carbon sugar. This is the first stable carbohydrate produced.
For every three CO₂ molecules fixed, six G3P molecules are produced. One G3P leaves the cycle to be used for making glucose or other organic compounds. The other five G3P molecules stay in the cycle.
Phase 3: Regeneration — Rebuilding RuBP
The five remaining G3P molecules (each with 3 carbons, so 15 carbons total) are rearranged through a series of reactions involving several enzymes. They combine and split to form three molecules of RuBP (each with 5 carbons, so 15 carbons total). This regeneration requires three more ATP molecules.
A common mistake is thinking the Calvin cycle produces glucose directly. It produces G3P, which is then used to build glucose and other carbohydrates elsewhere in the cell. One glucose requires two G3P molecules.
Why Six Turns? …
The "dark reaction" is so named because it does not itself depend directly on light energy, not because it happens in darkness.
- The stromal reactions of photosynthesis are not photochemical steps — unlike the membrane-based light reactions, they are not directly driven by light.
- However, they entirely depend on the ATP and NADPH supplied by the light reaction, so they cannot continue indefinitely without light having occurred.
- This is confirmed experimentally: after light is removed, the biosynthetic process continues briefly (using ATP/NADPH already made) and then stops, resuming only when light becomes available again. …
"Dark reaction" refers to the fact that these stromal steps are not themselves photochemical (light-absorbing) reactions, not that they occur in darkness — they still depend indirectly on the ATP and NADPH the light reaction supplies.
Within the chloroplast there is a clear division of labour. The membrane system — the grana and stroma lamellae — traps light energy and synthesises ATP and NADPH; because this is directly driven by light, these are called the light reactions. The stroma, on the other hand, carries out enzymatic reactions that synthesise sugar, and because these reactions are not themselves photochemical steps, they are conventionally called dark reactions or carbon reactions. …
Method 1 — Distinguish what 'dark reaction' actually means
- Recall the biosynthetic (stromal) reactions of photosynthesis are not themselves photochemical steps — they don't directly absorb light.
- Rule out (a) and (d): the reaction is not literally confined to darkness, nor does it run faster at night; it occurs in daylight too, alongside the light reaction.
- Rule out (c): the reaction is not blocked by daylight — plants clearly photosynthesise during the day. …
- TG EAPCET 2026Set ap-2026-05-04-FN1 markMCQQ.When 54 molecules of CO2 fixed by RuBisCo in a C3 plant, number of G3-P exported to cytosol and number of G3-P participate in regeneration phase respectively are (A) 90 and 18 (B) 54 and 54 (C) 60 and 48 (D) 18 and 90
›Reveal solutionSolution
Calvin-cycle stoichiometry: every 3 CO₂ fixed makes 6 G3P — 1 exported, 5 regenerate RuBP. For 54 CO₂: 18 exported and 90 for regeneration. Option (D).
The Calvin cycle runs in batches: for every 3 molecules of CO₂ fixed, 6 molecules of G3P are produced. Of these 6, exactly 1 is exported (net gain, used for sucrose/starch) and the remaining 5 are consumed to regenerate 3 molecules of RuBP (the CO₂ acceptor).
Scale this to 54 CO₂ fixed:
number of batches=354=18. …
- TG EAPCET 2025Set ap-2025-04-29-AN1 markMCQQ.In the given representation of C3 cycle, identify A, B and C and select the correct option (A) A – 3PGA, B – RUBP, C – Pyruvic acid (B) A – RUBP, B – 3PGA, C – Regeneration (C) A – PEP, B – OAA, C – Malic acid (D) A – PEP, B – RUBP, C – OAA
›Reveal solutionSolution
The C3 cycle involves the fixation of carbon dioxide by RuBP to form 3-PGA, followed by reduction and regeneration of RuBP. Therefore, A is RuBP, B is 3-PGA, and C is the regeneration phase. The correct option is (B).
The C3 cycle, also known as the Calvin cycle, is the primary pathway for carbon fixation in most plants. It occurs in the stroma of chloroplasts and uses the ATP and NADPH produced during the light-dependent reactions to convert carbon dioxide into glucose. The cycle can be broadly divided into three main phases: carboxylation, reduction, and regeneration. Understanding these phases is key to identifying the components.
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Carboxylation (Fixation of CO2):
The first step in the C3 cycle is the fixation of atmospheric carbon dioxide. This CO2 molecule combines with a five-carbon sugar, Ribulose-1,5-bisphosphate (RuBP). This reaction is catalyzed by the enzyme RuBisCO (Ribulose-1,5-bisphosphate carboxylase/oxygenase). The resulting six-carbon compound is highly unstable and immediately splits into two molecules of a three-carbon compound.
- Therefore, A represents the initial carbon dioxide acceptor, which is RuBP.
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Formation of the First Stable Product:
The unstable six-carbon intermediate formed after carboxylation quickly breaks down into two molecules of 3-Phosphoglyceric acid (3-PGA). This is a three-carbon compound and is the first stable product of the C3 cycle.
- Therefore, B represents the first stable product, which is 3-PGA.
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Reduction and Regeneration:
The 3-PGA molecules are then reduced to Glyceraldehyde-3-phosphate (G3P) using ATP and NADPH from the light reactions. Some of these G3P molecules are used to synthesize glucose, while the majority are used to regenerate RuBP. The regeneration of RuBP is crucial because it ensures the continuous operation of the cycle by providing the CO2 acceptor for subsequent rounds of carbon fixation. This regeneration process requires ATP. …
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- TG EAPCET 2025Set ap-2025-04-29-FN1 markMCQQ.Study the following lists and identify the correct matching pair to calvin cycle List-1 List-2 A. Number of ATP and NADPH required to fix one molecule of CO2 by C3 plants I. Six molecules B. One molecule of glucose in C3 cycle requires II. 18 ATP & 12 NADPH C. ATP and NADPH required to make one molecule of glucose III. 6CO2+18ATP+12NADPH D. Number of CO2 molecules required to form one molecule of glucose IV. 3 ATP & 2 NADPH (A) A – II, B – III, C – IV, D – I (B) A – I, B – IV, C – II, D – III (C) A – IV, B – III, C – I, D – II (D) A – IV, B – III, C – II, D – I
›Reveal solutionSolution
The Calvin cycle uses 3 ATP and 2 NADPH per CO2 fixed; for one glucose (6 CO2) that scales to 18 ATP and 12 NADPH. Matching these gives the correct pair: A–IV, B–III, C–II, D–I.
The Calvin cycle is the light-independent phase of photosynthesis where CO2 is reduced to carbohydrate. The key numbers — ATP and NADPH consumed per CO2 fixed — come from the stoichiometry of the cycle itself. Once you know those, scaling to a full glucose molecule is simple multiplication.
Let’s walk through each entry in List-1 and match it to the correct description in List-2.
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A. Number of ATP and NADPH required to fix one molecule of CO2 by C3 plants
In the Calvin cycle, each CO2 molecule that enters is reduced to a triose phosphate (like glyceraldehyde-3-phosphate). The cycle consumes 3 ATP and 2 NADPH per CO2 fixed.
So A matches IV (3 ATP & 2 NADPH).
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B. One molecule of glucose in C3 cycle requires
Glucose has 6 carbon atoms, so it takes 6 turns of the Calvin cycle (each fixing one CO2) to produce one glucose. The total requirement is therefore 6×(3 ATP+2 NADPH)=18 ATP+12 NADPH.
But the entry in List-2 for B is given as a chemical equation: 6CO2+18ATP+12NADPH — that’s exactly the overall input for one glucose. So B matches III.
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C. ATP and NADPH required to make one molecule of glucose …
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- TG EAPCET 2025Set ap-2025-04-30-FN1 markMCQQ.According to photosynthesis equation to produce 180g glucose and 193g oxygen, plant will absorb "X" g of carbondioxide and "Y" g water and consume "Z" K.cal of solar energy. 'X', 'Y' and 'Z' are respectively (A) X – 108 g, Y – 264 g, Z – 766.2 K.cal (B) X – 204 g, Y – 180 g, Z – 567.2 K.cal (C) X – 264 g, Y – 108 g, Z – 677.2 K.cal (D) X – 246 g, Y – 164 g, Z – 477.2 K.cal
›Reveal solutionSolution
The balanced photosynthesis equation and the law of conservation of mass give X=264 g of CO₂ and Y=108 g of H₂O; the standard energy requirement for 1 mole of glucose is 677.2 kcal, so Z=677.2 kcal. The correct option is (C).
The question is about the inputs and energy cost of photosynthesis. The overall reaction is:
6CO2+12H2Osolar energyC6H12O6+6O2+6H2O
Notice that water appears on both sides — 12 molecules are consumed but 6 are regenerated, so the net consumption of water is 6 molecules per glucose. The problem gives the products as 180 g glucose and 193 g oxygen. That 180 g is exactly 1 mole of glucose (molar mass 180 g/mol), and 193 g of oxygen is very close to 6 moles (6 × 32 = 192 g), so the reaction is producing 1 mole of glucose. The slight difference (193 vs 192) is likely a rounding in the problem statement; we work with exact molar masses.
Now we find X, Y, and Z.
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Find X (mass of CO₂ absorbed).
From the equation, 6 moles of CO₂ are needed per mole of glucose. Molar mass of CO₂ = 44 g/mol. So mass of CO₂ = 6×44=264 g. That is X.
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Find Y (mass of H₂O consumed).
Net consumption of water is 6 moles per mole of glucose. Molar mass of H₂O = 18 g/mol. So mass of H₂O = 6×18=108 g. That is Y.
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Find Z (solar energy consumed in kcal). …
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- TG EAPCET 2025Set ap-2025-04-30-FN1 markMCQQ.24 PGAL molecules are formed in C3 plant. Calculate the number of CO2 used and the number of G3P used for regeneration of RUBP molecules? (A) 12 CO2 & 24 G3P (B) 24 CO2 & 48 G3P (C) 12 CO2 & 20 G3P (D) 20 CO2 & 12 G3P
›Reveal solutionSolution
In the Calvin cycle, 24 PGAL (G3P) molecules correspond to 12 turns of the cycle, using 12 CO₂ molecules and requiring 20 G3P molecules for RuBP regeneration. The correct option is (C).
The key is to understand the stoichiometry of the Calvin cycle, not just memorise numbers. Every turn of the cycle fixes one CO₂ molecule into one molecule of 3-phosphoglycerate (3-PGA), which is then reduced to glyceraldehyde-3-phosphate (G3P, also called PGAL). But the cycle must also regenerate its starting acceptor, ribulose-1,5-bisphosphate (RuBP), and that regeneration consumes G3P molecules.
Let’s walk through the numbers carefully.
- Each CO₂ fixed produces two G3P molecules. One CO₂ combines with RuBP (a 5-carbon sugar) to form two molecules of 3-PGA (each 3-carbon). After reduction, each 3-PGA becomes one G3P. So 1 CO₂ → 2 G3P. If 24 G3P are formed, the number of CO₂ fixed is simply:
CO2=224=12
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But not all G3P leaves the cycle — most is used to regenerate RuBP.
For every 6 CO₂ fixed (i.e., 6 turns of the cycle), 12 G3P are produced. Of these 12 G3P:
- 2 G3P (equivalent to 6 carbons) are exported to make glucose or other products.
- The remaining 10 G3P (30 carbons) are used to regenerate 6 molecules of RuBP (each 5-carbon, total 30 carbons).
So the regeneration of 6 RuBP consumes 10 G3P. That’s a ratio:
6 RuBP10 G3P=35 G3P per RuBP
- Now apply this to our 12 CO₂ (12 turns). In 12 turns, the cycle produces 24 G3P. How many RuBP must be regenerated? Each turn consumes one RuBP, so 12 turns consume 12 RuBP. To regenerate 12 RuBP, the G3P required is:
- TG EAPCET 2024Set ap-2024-05-07-FN1 markMCQQ.Per one Calvin cycle the number of CO2, ATP utilized and the number of Glucose, NADPH molecules produced respectively are (A) 6 ; 18 ; 1 ; 12 (B) 6 ; 12 ; 1 ; 18 (C) 6 ; 1 ; 12 ; 18 (D) 12 ; 1 ; 6 ; 18
›Reveal solutionSolution
The Calvin cycle fixes 6 CO₂ molecules to produce one glucose molecule, consuming 18 ATP and 12 NADPH in the process. The correct pairing is 6 CO₂, 18 ATP, 1 glucose, 12 NADPH → option (A).
The Calvin cycle (light-independent reactions of photosynthesis) is often memorized in terms of inputs and outputs, but the numbers make more sense when you follow the carbon atoms. Each turn of the cycle fixes one CO₂ molecule, but it takes six turns to build one glucose (C₆H₁₂O₆). The trick is tracking the energy molecules (ATP and NADPH) consumed per CO₂ fixed, then multiplying by six.
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Per CO₂ fixed (one turn):
- 3 ATP are used (1 in the carboxylation step to regenerate RuBP, plus 2 in the reduction phase).
- 2 NADPH are used (both in the reduction of 3-PGA to G3P).
- One CO₂ enters, and after a series of rearrangements, the net gain is one-sixth of a glucose molecule (since 6 CO₂ → 1 glucose).
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For six CO₂ (one full glucose):
- CO₂ consumed: 6
- ATP used: 6×3=18
- NADPH used: 6×2=12
- Glucose produced: 1 …
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- TG EAPCET 2023Set ap-2023-05-10-FN1 markMCQQ.To reduce 1 CO2 in C3 cycle assimilatory power needed is (A) 2 ATP + 3 NADPH + H+ (B) 6 ATP + 2 NADPH + H+ (C) 5 ATP + 2 NADPH + H+ (D) 3 ATP + 2 NADPH + H+
›Reveal solutionSolution
The C3 cycle requires 3 ATP and 2 NADPH to fix one CO₂ into a three-carbon sugar. The correct option is (D).
The C3 cycle (Calvin cycle) is the light-independent phase of photosynthesis where CO₂ is fixed into carbohydrates. The "assimilatory power" refers to the ATP and NADPH (produced in the light reactions) that drive this cycle. For every molecule of CO₂ that enters the cycle, a specific number of ATP and NADPH molecules are consumed in the reduction steps. The key is to trace the fate of one CO₂ through the cycle, not the entire cycle's turnover for one glucose.
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Carboxylation: One CO₂ combines with RuBP (a 5-carbon compound) to form two molecules of 3-phosphoglycerate (3-PGA). This step uses no ATP or NADPH directly — it's powered by the enzyme RuBisCO.
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Reduction: Each 3-PGA is phosphorylated by ATP (to form 1,3-bisphosphoglycerate) and then reduced by NADPH (to form glyceraldehyde-3-phosphate, G3P). Since one CO₂ yields two 3-PGA molecules, this step consumes 2 ATP and 2 NADPH. …
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- TG EAPCET 2023Set ap-2023-05-10-AN1 markMCQQ.The reaction commonly involved in calvin cycle and aerobic respiration I. Phosphorylation II. Condensation III. Carboxylation IV. Dephosphorylation (A) I, II, III (B) I, III, IV (C) I, II, IV (D) II, III, IV
›Reveal solutionSolution
The Calvin cycle and aerobic respiration share phosphorylation, condensation, and dephosphorylation reactions, but carboxylation is unique to the Calvin cycle. The correct option is (C).
The question asks which reactions are commonly involved in both the Calvin cycle (photosynthesis) and aerobic respiration. This is a comparative biochemistry problem — you need to know the key reaction types that occur in each pathway and find the overlap.
Let’s break down each reaction type and see where it appears in both processes.
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Phosphorylation — This is the addition of a phosphate group to a molecule, often using ATP. In the Calvin cycle, phosphorylation occurs when RuBP (ribulose-1,5-bisphosphate) is regenerated and when 3-PGA is phosphorylated to form 1,3-BPGA. In aerobic respiration, substrate-level phosphorylation (e.g., in glycolysis and the Krebs cycle) and oxidative phosphorylation (electron transport chain) are central. So phosphorylation is common to both.
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Condensation — This is the joining of two molecules with the loss of water (or a small molecule). In the Calvin cycle, condensation happens when CO₂ is fixed to RuBP (forming an unstable 6-carbon intermediate that splits), and also when sugars are built. In aerobic respiration, condensation occurs in the Krebs cycle when acetyl-CoA combines with oxaloacetate to form citrate. So condensation is present in both.
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Carboxylation — This is the addition of a carboxyl group (-COOH). In the Calvin cycle, carboxylation is the very first step: RuBP + CO₂ → two molecules of 3-PGA, catalyzed by RuBisCO. In aerobic respiration, there is no carboxylation reaction — respiration breaks down carbon compounds, it does not add CO₂ to them. So carboxylation is not common to both. …
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- TG EAPCET 2023Set ap-2023-05-11-FN1 markMCQQ.Match the following List – I (Cycle/fixation name) A) First stable product of TCA cycle B) First stable product of C3 cycle C) First stable product of C4 cycle D) Product of nitrogen fixation List – II (Product formed)i) Ammoniaii) 3 PGAiii) OAAiv) Citric acid (A) A-ii, B-iii, C-i, D-iv (B) A-iii, B-ii, C-iv, D-i (C) A-iv, B-ii, C-iii, D-i (D) A-ii, B-iv, C-ii, D-iii
›Reveal solutionSolution
This question tests your knowledge of the initial stable products formed in various metabolic cycles and fixation processes. We will identify the first stable product for the TCA cycle, C3 cycle, C4 cycle, and nitrogen fixation, then match them to the given options. The correct option is (C).
The core idea behind this question is to test your understanding of the initial steps and key products of fundamental biochemical pathways. In many metabolic cycles, a substrate combines with an incoming molecule (like CO2 or acetyl-CoA) to form a new compound. The first stable compound formed after this initial reaction is often a defining characteristic of the pathway. Similarly, fixation processes convert an atmospheric or inorganic substance into a biologically usable form, and identifying the direct product of this conversion is crucial.
Let's break down each item and identify its first stable product.
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First stable product of TCA cycle:
The TCA cycle, also known as the Krebs cycle or citric acid cycle, begins with the condensation of acetyl-CoA (a 2-carbon compound) with oxaloacetate (a 4-carbon compound). This reaction is catalyzed by citrate synthase and results in the formation of a 6-carbon compound called citrate (citric acid). Citrate is the first stable product of the TCA cycle.
Acetyl-CoA (2C) + Oxaloacetate (4C) Citrate Synthase Citrate (6C)
Therefore, A matches with iv) Citric acid.
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First stable product of C3 cycle:
The C3 cycle, or Calvin cycle, is the primary pathway for carbon fixation in most plants. In this cycle, atmospheric carbon dioxide (CO2) is fixed by combining with a 5-carbon sugar, ribulose-1,5-bisphosphate (RuBP). This reaction is catalyzed by the enzyme RuBisCO. The resulting 6-carbon intermediate is highly unstable and immediately splits into two molecules of 3-phosphoglycerate (3-PGA), which is a 3-carbon compound. 3-PGA is the first stable product of the C3 cycle.
CO2 (1C) + RuBP (5C) RuBisCO Unstable 6C intermediate → 2 × 3-PGA (3C)
Therefore, B matches with ii) 3 PGA.
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First stable product of C4 cycle:
The C4 cycle is an adaptation found in some plants to minimize photorespiration, especially in hot and dry environments. In C4 plants, the initial carbon fixation occurs in mesophyll cells. Phosphoenolpyruvate (PEP), a 3-carbon compound, combines with atmospheric CO2. This reaction is catalyzed by PEP carboxylase. The product formed is oxaloacetate (OAA), a 4-carbon compound. OAA is the first stable product of the C4 cycle. …
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- TG EAPCET 2022Set ap-2022-07-31-FN1 markMCQQ.How many ATP and NADPH molecules are required for fixation of 12 CO2 molecules through Calvin cycle respectively? (A) 36, 24 (B) 18, 12 (C) 30, 24 (D) 36, 20
›Reveal solutionSolution
The Calvin cycle uses 3 ATP and 2 NADPH per CO₂ fixed. For 12 CO₂, that’s 36 ATP and 24 NADPH. The correct option is (A).
Why this approach works
The Calvin cycle is the light-independent phase of photosynthesis, where CO₂ is reduced to carbohydrate. Each turn of the cycle fixes one molecule of CO₂, but the energy and reducing power come from ATP and NADPH produced in the light reactions. The key is knowing the stoichiometry per CO₂ fixed:
- In the carboxylation step, RuBP (a 5-carbon sugar) combines with CO₂.
- In the reduction phase, 1,3-bisphosphoglycerate is reduced to glyceraldehyde-3-phosphate (G3P) using NADPH and ATP.
- In the regeneration phase, RuBP is rebuilt using additional ATP.
The classic textbook numbers are 3 ATP and 2 NADPH per CO₂. This is a fixed ratio, so scaling to 12 CO₂ is straightforward multiplication.
Step-by-step reasoning
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Recall the per-CO₂ requirement
For every CO₂ molecule fixed in the Calvin cycle:
- 3 molecules of ATP are consumed (1 in the carboxylation phase for phosphorylation of 3-phosphoglycerate, and 2 in the regeneration of RuBP).
- 2 molecules of NADPH are consumed (both in the reduction of 1,3-bisphosphoglycerate to G3P). This is a standard result from the cycle’s biochemistry.
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Scale to 12 CO₂ molecules
Multiply the per-CO₂ numbers by 12:
- ATP: 3×12=36 …
- TG EAPCET 2022Set ap-2022-07-31-AN1 markMCQQ.Arrange the following reactions in a sequence that occur in Calvin cycle. A) Carboxylation B) Regeneration C) Reduction D) Oxidation (A) A, C, B (B) A, B, C (C) B, C, D (D) A, B, D
›Reveal solutionSolution
The Calvin cycle proceeds in three ordered phases: carboxylation (fixing CO₂), reduction (making sugar), and regeneration (rebuilding RuBP). The correct sequence is A, C, B, which corresponds to option (A).
The Calvin cycle is the light-independent phase of photosynthesis, where carbon dioxide is fixed into organic molecules. It doesn't happen in darkness alone — it's called "dark reaction" only because it doesn't directly need light, but it does use the ATP and NADPH produced in the light reactions.
The key insight is that the cycle has three distinct phases, and they must happen in a specific order. You can't reduce something that hasn't been fixed yet, and you can't regenerate the starting molecule until you've made the sugar and have leftover carbon skeletons.
Let's walk through each phase in the correct sequence.
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Carboxylation (A) — This is the first step. The enzyme RuBisCO attaches CO₂ to a 5-carbon molecule called RuBP (ribulose bisphosphate). This forms an unstable 6-carbon intermediate that immediately splits into two molecules of 3-phosphoglycerate (3-PGA), each with 3 carbons. Without this step, no carbon enters the cycle at all.
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Reduction (C) — Now the 3-PGA molecules get reduced. ATP donates a phosphate to make 1,3-bisphosphoglycerate, then NADPH donates electrons to convert it into glyceraldehyde-3-phosphate (G3P), a 3-carbon sugar. This is where the actual carbohydrate is produced. One G3P molecule exits the cycle to be used for glucose or other sugars; the rest stay in.
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Regeneration (B) — The remaining G3P molecules (five of them, for every three CO₂ fixed) are rearranged using more ATP to rebuild three molecules of RuBP. This completes the cycle, allowing it to start again. Without regeneration, the cycle would run out of RuBP and stop. …
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